1. Given the Keq of the following reaction is 0.5 calculate the standard free energy change (G) glucose-6-PO4fructose-6-PO4 G0r= In what direction does this reaction proceed? 2. The intracellular concentration of glucose-6-phosphate and fructose-6-phosphate are measured inside the cell of a patient and the following values were obtained: [glucose-6-phosphate] =8105M [fructose-6-phosphate] =1.5105M Is this reaction at equilibrium? What is the value of Q ? What do you predict the sign for G will be? Calculate G for this reaction