1 L = D + DH+Y/ dL D 2 V (TITH 300) + 4 (H+D-12+5) - = D+H+ VTDH + 4 = 0 + 2D + 2H + (TVDH) + 4 = 0 2 dl = D + VID +4=0 dH 3 dL = dv a 4D + VD + 44=0 TIDH - 300 = 0 TDH-1200 = 0 4 H + D = 12 + 5 = 0 2H + D-24+25=0 4|d2 = H+D- du 5/dL ds = 245=0 F 4=0 and So H Two switching cases: * u=0 2 4D+TvD) +44 = 0 = TUD = -4D V = -4 TI) 3 TTDSH-1200=0 TN => = 1200 H = 1200 1 2D + 2H + (TvDH) +4=0 2D + 2 (1200) + T(-4) D (1200). 2D + 2400 -. 4800=0 D - 1200 TW 21-2400-0 D = 1200 D =0 42H+D-24+25 = 0 = 25% = 24-2H-D Solving for D. H, V, S S=24-2H-D 2.3H-> D = 1200 D = 381.972 D= 7.256 H = 1200 H = 1200 TTD => H = 1200 H=7.256. (7.256 165.403 22.795 V= -4 V=-4 =-0.175 TTD 5 = 24-2H-D S=24-14.512-7.256 5, 1.116 2 2 f = D + DH f= 7.256, (7.256) (7.256) f=26.325+ 52.649 + = 2 a f=78.974 * S-o Can only be solved using roots. 3H = 1200 TID 4/24+D-24+25=0 2H-24-D H = 24-D a 1200 =24-D * 2400 = 24D-D TTD - 24TD) + 2400=0 TID 2 Command Window >> clear all >> D=roots ([pi,-24*pi, 0,2400]) D= 22.4896 6.6322 -6.121 >> H(24-D)/2 H= 0.7552 8.6839 14.5609