Question
1. Let V be a real vector space. We know that V has an additive identity, called 0. Suppose there is a vector u V
1. Let V be a real vector space. We know that V has an additive identity, called 0. Suppose there is a vector u V with the property that u+v=vforeveryvV. Showthatu=0. (This shows that are a real vector space can only have one additive identity.)
2. Let V be a real vector space, and suppose that U1 and U2 are both subspaces of V . The intersection of U1 and U2, written U1 U2, is the setofallvectorsvV suchthatvU1 andvU2. ShowthatU1U2 isa subspace of V .
3. Let V be a real vector space, and suppose that U1 and U2 are both subspaces of V . The union of U1 and U2, written U1 U2, is the set of all vectorsvV suchthatvU1 orvU2.IsU1U2 necessarilyasubspaceof V ? If yes, prove it, if not, describe a counterexample.
4. Suppose that U, V , and W are all real vector spaces, and that T1 : U V and T2 : V W are both linear transformation. The composition T2 T1 is the function from U to W defined by (T2 T1)(u) = T2(T1(u)), for all u U . Show that T2 T1 is also a linear transformation.
5. Consider a linear transformation T : Rn Rm. Let G be the subset of Rn+m, consisting of all points (x1, . . . xn, xn+1, . . . xn+m) such that T(x1,...xn) = (xn+1,...xn+m). Show that G is a subspace of Rn+m.
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