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1 . Let x be the number to translate: find p , the largest power of 2 smaller equal to x p = | l
Let be the number to translate: find the largest power of smaller equal to
How many times does fit into the number
if otherwise
Set to the remainder of the number not yet translated.
While the remainder is not zero, reduce by and go back to step
Task: How would you modify the algorithm to incorporate a for loop?
Problem requests a fixed number of mantissa bits:
Can we simplify the algorithm if we know the number of mantissa bits to use?
How would steps need to be changed to convert the algorithm's while loop into a for loop?
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