Question
1) margin error 2: A sample of heights of 124 American men yield a sample average of 58.87 inches. What would be the margin of
1) margin error 2: A sample of heights of 124 American men yield a sample average of 58.87 inches. What would be the margin of error for a 95.44% CI of the average height of all such men if the population deviation is 2.9 inches? Round to the nearest hundredth
2) margin error 3 t: A sample of weights of 51 boxes of cereal yield a sample average of 16.1 ounces. What would be the margin of error for a 96% CI of the average weight of all such boxes if the sample deviation is 0.53 ounces? The population of all such weights is normally distributed. Round to the nearest hundredth
3) margin error 2 t: A sample of weights of 31 boxes of cereal yield a sample average of 17.7 ounces. What would be the margin of error for a 95% CI of the average weight of all such boxes if the sample deviation is 0.56 ounces? The population of all such weights is normally distributed. Round to the nearest hundredth
4) margin error 4: A sample of heights of 175 American men yield a sample average of 57.82 inches. What would be the margin of error for a 99.74% CI of the average height of all such men if the population deviation is 3.2 inches? Round to the nearest hundredth
5) Choose t or z 5: A confidence interval is to be found using a sample of size 876 and the sample deviation of 5.312. If the critical value should be a z-score, type the number 0 below If the critical value should be a t-score, type the number 1 below *The computer is looking for either the input 0 or the input 1. It will not recognize anything else you type in
6)
Alpha represents the complement of confidence
a. | TRUE | |
b. | FALSE |
7) Choose t or z: A confidence interval is to be found using a sample of size 10 and a known population deviation of 1.621. If the critical value should be a z-score, type the number 0 below If the critical value should be a t-score, type the number 1 below *The computer is looking for either the input 0 or the input 1. It will not recognize anything else you type in
8)
Increasing the confidence level will reult in using larger critical values in a confidence interval
a. | TRUE | |
b. | FALSE |
9)
All things being equal, the margin of error of a confidence interval will decrease as
a. | The confidence level increases | |
b. | The population standard deviation increases | |
c. | The sample size increases | |
d. | The sample size decreases |
10) Choose t or z 2: A confidence interval is to be found using a sample of size 57 and a known population deviation of 1.326. If the critical value should be a z-score, type the number 0 below If the critical value should be a t-score, type the number 1 below *The computer is looking for either the input 0 or the input 1. It will not recognize anything else you type in
11)
A confidence interval for mu is centered on the sample mean
a. | TRUE | |
b. | FALSE |
12)
A region in which there is a high certainty of locating the populatiion mean mu
a. | Critical Value | |
b. | Confidence Interval | |
c. | Margin of Error | |
d. | Sigma x-bar |
13) alpha 2: If a confidence level of 95.44% is being used to construct a confidence interval, then what would be the value of alpha? Answer in decimal form.
14) DF1: What would be the degree of freedom for a sample of size 247?
15) simple interval 2 t: If a sample average is found to be 98.58, and the margin of error is calculated to be 0.23, then the upper end of the confidence interval for mu would be ______
16) Simple interval 3 t: If a sample average is found to be 18.2, and the margin of error is calculated to be 0.08, then the lower end of the confidence interval for mu would be ______
17) simple interval 4 t: If a sample average is found to be 98.62, and the margin of error is calculated to be 0.17, then the lower end of the confidence interval for mu would be ______
18) simple interval 1: If a sample average is found to be 60.2, and the margin of error is calculated to be 2.2, then the upper end of the confidence interval for mu would be ______
19) SAMPLE SIZE 2: A confidence interval for the average adult male height is to be constructed at a 95% confidence. If the population deviation for the data in question is 4.1 inches, and the researcher desires a margin of error of 0.72 inches, then what should be the sample size?
20) SAMPLE SIZE 1: A confidence interval for the average healthy human body temperature is to be constructed at a 90% confidence. If the population deviation for the data in question is 0.33degrees F, and the researcher desires a margin of error of 0.03degrees F, then what should be the sample size?
21) STI83 interval 7: Use your TI83 to find the lower end of the interval requested: A 99% confidence interval for the average wight of a standard box of Frosted Flakes if sample of 56 such boxes has an average weight of 16.7 ounces with a population deviation of 0.4 ounces round to the nearest hundredth of an ounce
22) TI83 interval 6 t: Use your TI83 to find the upper end of the interval requested: A 99.0% confidence interval for the average healthy human body temperature if a sample of 17 such temperatures have an average of 98.52 degrees F with a sample deviation of 0.276 degrees F The population of all such temperatures is normally distributed round to the nearest hundreth of a degree
23) TI83 interval 2 t: Use your TI83 to find the upper end of the interval requested: A 96.0% confidence interval for the average height of the adult American male if a sample of 51 such males have an average height of 59.1 inches with a sample deviation of 3.1 inches. The population of all such heights is normally distributed round to the nearest hundreth of an inch
24) STI83 interval 6: Use your TI83 to find the lower end of the interval requested: A 98% confidence interval for the average height of the adult American male if a sample of 353 such males have an average height of 58.0 inches with a population deviation of 3.2 inches round to the nearest hundredth of an inch
25) TI83 interval 10 t: Use your TI83 to find the lower end of the interval requested: A 90.0% confidence interval for the average weight of a box of cereal if a sample of 12 such boxes has an average of 16.60 ounces with a sample deviation of 0.212 ounces. The population of all such weights is normally distributed round to the nearest hundreth of an ounce
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