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1 mol Al_(2)O_(3)=(((6.02)10^(23)molecules ))/(mol )= ((5 atoms ))/(Al_(2)O_(3) molecule )=3.0110^(24)atoms

1 mol Al_(2)O_(3)=(((6.02)*10^(23)molecules ))/(mol )= ((5 atoms ))/(Al_(2)O_(3) molecule )=3.01*10^(24)atoms

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