1 mol of gas mixture (contains (59) vol.% CO and 41 vol.% N₂) is burnt completely with stoichiometric amount of dry air at 298 K. Dry air contains 21 vol.% O₂ and 79 vol.% N₂.

CO + O₂ = CO₂

H298, CO (g) = -110000 J.mol-1 H298, CO2 (g) = -393500 J.mol-1 H298, O2 (g) = 0 J.mol-1 H298, N2 (g) = 0 J.mol-1

CP, CO = 34.00 J.K-1.mol-1 CP, CO2 = 45.14 + 9.04x10-3 T J.K-1.mol-1 CP, O2 = 29.96 + 4.18x10-3 T 1.67x105 T-2 J.K-1.mol-1 CP, N2 = 27.87 + 4.27x10-3 T J.K-1.mol-1

Calculate the maximum flame temperature (K).