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1. Only red boxes I don't know what I did wrong Consider the integral /4x3 In(x) dac: Applying the integration by parts technique, let u

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1. Only red boxes I don't know what I did wrong

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Consider the integral /4x3 In(x) dac: Applying the integration by parts technique, let u = In (x) V and du = 2.3 x dx culus Then du = dx and v = 24 X 5 ac 4 Then uv - udu = ns In(x) 24 X X S & Ve 4 4x dx try Integration gives the final answer x4 In (x) - +c metry

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