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1) Part A In a 1.26 T magnetic field directed vertically upward, a particle having a charge of magnitude 9.00 /C and initially moving northward

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Part A In a 1.26 T magnetic field directed vertically upward, a particle having a charge of magnitude 9.00 /C and initially moving northward at 4.64 km /s is deflected What is the sign of the charge of this particle? toward the east. O The charge is negative. O The charge is positive. Submit Previous Answers Correct V Part B Find the magnetic force on the particle. AED ? F = N Submit Request AnswerPart B Find the magnitude of the force this magnetic field exerts on the proton. A proton traveling at 3.70 km/s suddenly enters a uniform magnetic field of 0.740 T , traveling at an angle of 55.0 with the field lines (see the figure (Figure 1)). F = N Submit Request Answer Part C If you can vary the direction of the proton's velocity, find the magnitude of the maximum and minimum forces you could achieve. Answer the question in the order indicated. Separate your answers using comma. AEQ 0 8 ? Fmaz, Fmin = N Submit Request Answer Part D Part E Part F Figure F - N 8.00 A Submit Request Answer Provide FeedbackPart A Learning Goal: To understand the magnetic force on a straight current-carrying wire in a uniform magnetic field. Consider a wire of length L = 0.30 m that runs north-south on a horizontal surface. There is a current of 1 = 0.50 A flowing north in the wire. (The rest of the circuit, which actually delivers this current, is not shown.) The Earth's magnetic field at this location has a magnitude of 0.50 gauss (or, in SI units, 0.5 x 10- tesla) and points north and 38 degrees down from the horizontal, Magnetic fields exert forces on moving charged particles, whether those charges toward the ground. What is the size of the magnetic force on the wire due to the Earth's magnetic field? In considering the agreement of units, recall that 1 T = 1 N/(A . m).(Figure 1) are moving independently or are confined to a current-carrying wire. The magnetic force F on an individual moving charged particle depends on its velocity v and Express your answer in newtons to two significant figures. charge q. In the case of a current-carrying wire, many charged particles are simultaneously in motion, so the magnetic force depends on the total current I View Available Hint(s) and the length of the wire L. The size of the magnetic force on a straight wire of length L carrying current I in AEd a uniform magnetic field with strength B is EX ? F = ILB sin(0). 4.62E - 6 N Here O is the angle between the direction of the current (along the wire) and the direction of the magnetic field. Hence B sin(0) refers to the component of the You have already submitted this answer. Enter a new answer. magnetic field that is perpendicular to the wire, B1 . Thus this equation can also No credit lost. Try again. be written as F = ILBI. The direction of the magnetic force on the wire can be described using a "right- hand rule." This will be discussed after Part B. Submit Previous Answers Part B The direction of the magnetic force is perpendicular to both the direction of the current flow and the direction of the magnetic field. Here is a "right-hand rule" to help you determine the direction of the magnetic force. (Figure 2) 1. Straighten the fingers of your right hand and point them in the direction of the current. 2. Rotate your arm until you can bend your fingers to point in the direction of the magnetic field. Figure Submit Previous Answers Request Answer b C X Incorrect; Try Again; 5 attempts remaining -> Hinge 20.0 cm Provide Feedback ak 35.0 cm >dPart A You want to produce a magnetic field of magnitude 5.50x10-4 T at a distance of 4.00x10-2 m from a long, straight wire. What current is required to produce this field? AEQ ? OC B E n K TL O T X US A E X h E = 47 . 10 -7 A Submit Previous Answers Request Answer X Incorrect; Try Again; 3 attempts remaining V Part B With the current found in part A, how strong is the magnetic field 8.00 cm from the wire's center? ? B= 2.75 . 10e-4 T Submit Previous Answers Request Answer X Incorrect; Try Again; 5 attempts remainingPart A Two insulated wires perpendicular to each other in the same plane carry currents as shown in the figure (Figure 1). Assume that I = 10 A and d = 18 cm . Find the magnitude of the net magnetic field these wires produce at points P and Q if the 10 A current is to the right. Express your answers using two significant figures separated by a comma. BP, BQ = T Submit Request Answer Part B Find the magnitude of the net magnetic field these wires produce at points P and Q if the 10 A current is to the left. Express your answers using two significant figures separated by a comma. AEd Bp, Bo = T Submit Request Answer Figure cm (b)f 8.0 cm d P

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