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(1 point) A spherical snowball is melting so that its diameter is decreasing at rate of 0.2 cm/min. At what is the rate is the volume of the snowball changing when the diameter is 8 cm? The volume is changing at a rate of cm3/ min.(1 point) This problem will lead you through the steps to answer this question: A spherical balloon is being inflated at a constant rate of 20 cubic inches per second. How fast is the radius of the balloon changing at the instant the balloon's diameter is 12 inches? Is the radius changing more rapidly when d = 12 or when d = 16? Why? Draw several spheres with different radii, and observe that as volume changes, the radius, diameter, and surface area of the balloon also change. Recall that the volume of a sphere of radius r is V = = mrs. Note that in the setting of this problem, both V and r are changing as time t changes, and thus both and r may be viewed as implicit functions of t, with respective derivatives - and ax Differentiate both sides of the equation V = = Tr with respect to t (using the chain rule on the right) to find a formula for that depends on both r and dV dt At this point in the problem, by differentiating we have "related the rates" of change of V and r. Recall that we are given in the problem that the balloon is being inflated at a constant rate of 20 cubic inches per second. To which derivative does this rate correspond? dV It O D. None of these From the above discussion, we know the value of at every value of t. Next, observe that when the diameter of the balloon is 12, we know the value of the radius. In the equation dV = 4mr dr dt at substitute these values for the relevant quantities and solve for the remaining unknown quantity, which is . How fast is the radius changing at the instant when d = 12? How fast is the radius changing at the instant when d = 16? When is the radius changing more rapidly, when d = 12 or when d = 16? O A. when d = 12 OB. when d = 16 O C. Neither; the rate of change of the radius is constant