(1 point) A spring with a 6-kg mass and a damping constant 5 can be held stretched 2 meters beyond its natural length by a force of 8 newtons. Suppose the spring is stretched 4 meters beyond its natural length and then released with zero velocity, In the notation of the text, what is the value c 4mk? mkg/sec Find the position of the mass, in meters, after t seconds. Your answer should be a function of the variable t with the general form cet cos(t) + ce sin(St) B = y = 8 = C = C2