Question
(1 point) Find the area of the surface obtained by rotating the curve $$ x=6 t-frac{6}{3} t^{3}, y=6 t^{2}, 0 leq t leq 1
(1 point) Find the area of the surface obtained by rotating the curve $$ x=6 t-\frac{6}{3} t^{3}, y=6 t^{2}, 0 \leq t \leq 1 $$ about the $x$-axis. Surface Area = CS.VS. 1421|
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Mobile Communications
Authors: Jochen Schiller
2nd edition
978-0321123817, 321123816, 978-8131724262
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