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(1 point) In this problem we consider an equation in differential form M de + N dy = 0 The equation (3y + Axle 3)

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(1 point) In this problem we consider an equation in differential form M de + N dy = 0 The equation (3y + Axle 3) dx + (1 - by'e * )dy = 0 in differential form M de + NV dy - 0 is not exact. Indeed, we have M. - N . = For this exercise we can find an integrating factor which is a function of I alone since M, N . N can be considered as a function of z alone Namety we have A() Multiplying the original equation by the integrating factor we obtain a new equation M de + N dy = 0 where M Which is exact since M.= are equal This problem is exact. Therefore an implicit general solution can be written in the form F(z, y) - C where F(z.v) = Finally find the value of the constant C so that the initial condition (0) = 1. C

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