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( 1 point ) In this problem we will crack RSA. Suppose the parameters for an instance of the RSA cryptosystem are N = 4

(1 point) In this problem we will crack RSA. Suppose the parameters for an instance of the RSA cryptosystem are N=4661,e=5.(1 point) The speed of RSA hinges on the ability to do large modular exponentiations quickly.
While e can be made small, d generally cannot.
A popular method for fast modular exponentiation is the Square and Multiply algorithm.
Suppose that N=19511 and d=3845. We want to use the Square and Multiply algorithm to quickly decrypt y=17512.
a) Express d as a binary string (e.g.10110110).SQ,MUL,SQ,SQ,SQ,MUL,SQ,SQ,MUL,SQ,SQ.
c) What is x=ydmodN ?
We have obtained some ciphertext y=1046.
a) Factor N=4661 into its constituent primes p and q.
min(p,q)=
max(p,q)=
b) Compute (N).
(4661)=
c) Compute d, the decryption exponent.
d=
d) Decrypt y=1046 to find the plaintext.
x=
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