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(1 point) Let f (x) = x2 - 5x. (A) Find the slope of the secant line joining (3, f(3)) and (7, f(7)). Slope of
(1 point) Let f (x) = x2 - 5x. (A) Find the slope of the secant line joining (3, f(3)) and (7, f(7)). Slope of secant line = (B) Find the slope of the secant line joining (5, f(5)) and (5 + h, f(5 + h)). Slope of secant line = (C) Find the slope of the tangent line at (5, f(5)). Slope of tangent line = (D) Find the equation of the tangent line at (5, f (5)). VE(1 point) Let f(x) = 37 - x2 The slope of the tangent line to the graph of f(x) at the point (-6, 1) is The equation of the tangent line to the graph of f(x) at (-6, 1) is y = mx + b for m= and b = Hint: the slope at x = -6 is given by f(-6+ h) - f(-6) m = lim h-0 h
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