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(1 point) Let f(x) = x 148 cos 2x sin z. Find f2020 (0). f2020 (0) = (1 point) Let f(x) = V. By considering
(1 point) Let f(x) = x 148 cos 2x sin z. Find f2020 (0). f2020 (0) = (1 point) Let f(x) = V. By considering the Taylor polynomial T2 (2) of degree 2 generated by f() at the point 2 = 100, approximate 107 by T (101) V101 By Taylor's theorem, there exists c (100, 101) such that the error of the above approximation is f"() (101 - 100) 3! Hence, estimate the absolute error by giving an upper bound without The absolute value - 3! Remark Instead of putting a large upper bound, You should give the upper bound as sharp as you can | Find the Taylor polynomial T. (2) generated by the function f(x) = el-22) at x = 0. Ta(z) = Lys(a) de f(x) da Using the above, approximate 1/2 -1/2 (1 point) Let f(x) = x 148 cos 2x sin z. Find f2020 (0). f2020 (0) = (1 point) Let f(x) = V. By considering the Taylor polynomial T2 (2) of degree 2 generated by f() at the point 2 = 100, approximate 107 by T (101) V101 By Taylor's theorem, there exists c (100, 101) such that the error of the above approximation is f"() (101 - 100) 3! Hence, estimate the absolute error by giving an upper bound without The absolute value - 3! Remark Instead of putting a large upper bound, You should give the upper bound as sharp as you can | Find the Taylor polynomial T. (2) generated by the function f(x) = el-22) at x = 0. Ta(z) = Lys(a) de f(x) da Using the above, approximate 1/2 -1/2
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