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1. Problems 1 through 5 will used hexadecimal notation to represent bytes. The following table can be used to perform an XOR operation on hexadecimal
1. Problems 1 through 5 will used hexadecimal notation to represent bytes. The following table can be used to perform an XOR operation on hexadecimal digits: 10 1 2 3 4 5 6 7 8 9 a b c d e f - 0 1 2 3 4 5 6 7 8 9 a b c d e f 1/1 0 3 2 5 4 7 6 98 ba dcfe 212 3 0 1 6 7 4 5 a b 89efcd 313 2 1 0 7 6 5 4 b a 98 fedo 4|4 5 6 7 0 1 2 3 cd e f 89 a b 515 4 7 6 1 0 3 2 dcfe98 ba 616 7 4 5 2 3 0 1 e fcd a b 8 9 717 6 5 4 3 2 1 0 fedcba 9 8 8/89 a b c d e f 0 1 2 3 4 5 6 7 919 8 badcfe 10 3 2 5 4 7 6 ala b89efcd 2 3 0 16 7 4 5 bb a 98 fedc 3 2 1 0 7 6 5 4 clc d e f 89 a b 4 5 6 7 0 1 2 3 dldcfe98 b a 5 4 7 6 1 0 3 2 ele fcd a b 8 9 6 7 4 5 2 3 0 1 flfedcba 9 8 7 6 5 4 3 2 1 0 For example, 5 d would give the entry in row 5 column d, which is 8 Given a plaintext block P and a round key K, with the following values: P=00010203 04050607 08090AOB OCODOEOF Ko = 46369cf7 9345246d 450856fb 70c62e3e what would the internal state be after the initial AES AddRoundKey layer
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