1. Suppose that the probability that an adult in America will watch the Super Bowl is 45%. Each person is considered independent. We are interested in the number of adults in America we must survey until we find one who will watch the Super Bowl.

(a)In words, define the Random Variable X.

a. the number of adults surveyed until one who watches the Super Bowl is found

b. the favorite team of the adult

c. the adult's opinion regarding the Super Bowl

d. the number of adults who watch the Super Bowl

(b)List the values that X may take on.

a. X = 0, 1, 2, ...

b. X = 1, 2, 3, ...

c. X = 1, 2, 3, ..., 98, 99, 100

d. X = 45

(c)Give the distribution ofX. X~ ____ ( ____ , ____ )

(d)How many adults in America do you expect to survey until you find one who will watch the Super Bowl? (Round your answer to the nearest whole number.) _____ adults

(e)Find the probability that you must ask 9 people. (Round your answer to four decimal places.)

(f)Find the probability that you must ask 5 or 6 people. (Round your answer to four decimal places.)

2. The heights of the 430 National Basketball Association players were listed on team rosters at the start of the 2005-2006 season. The heights of basketball players have an approximately normal distribution with mean,

? = 79 inches

and a standard deviation,

? = 3.89 inches.

a)For the following height, calculate the z-score and interpret it using complete sentences. (Round your answer to two decimal places.)

73 inches

The z-score is _____ . An NBA player whose height is 73 inches is (---Select--- shorter than or taller than) average.

(b)For the following height, calculate the z-score and interpret it using complete sentences. (Round your answer to two decimal places.)

82 inches

The z-score is _____ . An NBA player whose height is 82 inches is (---Select--- shorter than or taller than) average.

(c)If an NBA player reported his height had a z-score of 3.6, would you believe him? Explain your answer. (Round your answer to two decimal places.)

A z-score of 3.6 equates to a height of ______ inches. There are (---Select--- many or few) NBA players this tall, so it is (---Select--- unlikely or likely) that the player's z-score is 3.6.

3. According to a study done by De Anza students, the height for Asian adult males is normally distributed with an average of 66 inches and a standard deviation of 2.5 inches. Suppose one Asian adult male is randomly chosen. Let X = height of the individual.

(a)Give the distribution of X. X ~ _____ ( _____, _____ )

(b)Find the probability that the person is between65and69inches. Write the probability statement.

P ( _____ X

What is the probability? (Round your answer to four decimal places.)

_______

a.