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1. Suppose we are going to store the 32 bit integer 0x12ab34cd at memory address 0x100. Our memory is byte-addressable, which means that each memory

1. Suppose we are going to store the 32 bit integer 0x12ab34cd at memory address 0x100. Our memory is byte-addressable, which means that each memory address stores a single byte.

(a) What byte is stored at address 0x101 if our architecture is big endian?

(b) What byte is stored at address 0x101 if our architecture is little endian?

2. (x << 3) + (x << 5) = x * N, where N is some constant. What is N (in base 10)?

3.Compute the 4 result for these integer additions.

(a) 1011 + 0110

(b) 0110 + 0010

(c) 1001 + 1010

write answer in 4-bit:

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