1) The concentration of potassium ions outside the cell is 0.5 times the number used in class. All other concentrations are the ones used in class. [111m 511110? 25m 1.\" 111-1111111121) [Kai] IN = lblOml/l 1N=2611mevxm(%%%%-:-01o1V\" The potential calculated in class, -0.089, is less than the above calculated potential of -0. 107 because the concentration of ions outside of the cell has increased in the above scenario. Hence, the outside is more positive, while the inside of the cell is more negative. 7-) EQUILIBRIUM POTENTIAL a; (0 1111193 Io1o1]=o1o1v EQUILIBRIUM POTENTIAL a; Mac m; 0.0%! CURRENT CALCULATION : POTENTIAL DIFF. of SODIUM= AV "I'PGO V,\" = 0V \" @GMV" (0.911611% 1' i00nWAD 0.0%V'I(00:1)'I(100)+0.10?\\/'0 V,\" = , 852 0.066V+0.10V -I(1oon)+r(100n) POTENTIAL DIFF. of PoTAssww o113v1:(soon) V111 = 011 + 107mm! (o.111;mA x lOOn[%D 3031113? 11610391 02113111131 V111 ' '85.\"! Current moves to the left