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1. The function f(x,y) = 4xy has an absolute maximum value and absolute minimum value subject to the constraint 2x2 + 2y -3xy =49. Use
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The function f(x,y) = 4xy has an absolute maximum value and absolute minimum value subject to the constraint 2x2 + 2y -3xy =49. Use Lagrange multipliers to find these values. The absolute maximum value is The absolute minimum value isFind the critical points of the following function. Use the Second Derivative Test to determine (if possible) whether each critical point corresponds to a local maximum, local minimum, or saddle point. If the Second Derivative Test is inconclusive, determine the behavior of the function at the critical points. f(x,y) =7x7+2xy -5x +1 What are the critical points? (Type an ordered pair. Use a comma to separate answers as needed.) Use the Second Derivative Test to find the local maxima. Select the correct choice below and, if necessary, fill in the answer box within your choice. O A. The test shows that there is/are local maxima at (Type an ordered pair. Use a comma to separate answers as needed.) O B. The test does not reveal any local maxima and there are no critical points for which the test is inconclusive, so there are no local maxima. 22 O C. The test does not reveal any local maxima, but there is at least one critical point for which the test is inconclusive.Use the Second Derivative Test to find the local minima. Select the correct choice below and, if necessary, fill in the answer box within your choice. O A. The test shows that there is/are local minima at (Type an ordered pair. Use a comma to separate answers as needed.) O B. The test does not reveal any local minima and there are no critical points for which the test is inconclusive, so there are no local minima. O C. The test does not reveal any local minima, but there is at least one critical point for which the test is inconclusive. Use the Second Derivative Test to find the saddle points. Select the correct choice below and, if necessary, fill in the 22 answer box within your choice. O A. The test shows that there is/are saddle points at (Type an ordered pair, Use a comma to separate answers as needed.) B. The test does not reveal any saddle points and there are no critical points for which the test is inconclusive, so there are no saddle points. O C. The test does not reveal any saddle points, but there is at least one critical point for which the test is inconclusive.O A. Among these points, there are local minimum/minima at , saddle point(s) at , and no local maxima. (Type an ordered pair. Use a comma to separate answers as needed.) O B. Among these points, there are local maximum/maxima at , local minimum/minima at , and saddle point(s) at (Type an ordered pair. Use a comma to separate answers as needed.) O C. Among these points, there are local minimum/minima at , and no local maxima or saddle points. (Type an ordered pair. Use a comma to separate answers as needed.) O D. Among these points, there are local maximum/maxima at , saddle point(s) at , and no local minima. (Type an ordered pair. Use a comma to separate answers as needed.) O E. Among these points, there are local maximum/maxima at , and no local minima or saddle points. (Type an ordered pair. Use a comma to separate answers as needed.) OF. Among these points, there are local maximum/maxima at local minimum/minima at , and no saddle points. (Type an ordered pair. Use a comma to separate answers as needed.) O G. Among these points, there are saddle point(s) at . and no local maxima or minima. (Type an ordered pair. Use a comma to separate answers as needed.) OH. The Second Derivative Test is conclusive for each critical pointStep by Step Solution
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