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1. Two point-charges Q and Q are 2.8 m apart, and their total charge is 31 C. If the force of repulsion 1 between
1. Two point-charges Q and Q are 2.8 m apart, and their total charge is 31 C. If the force of repulsion 1 between them is 0.2614 N, what are magnitudes of the two charges by following the steps below? (a) Q + Q = Use Coulomb's (b) Q X Q = 31x10 -6 C Law to calculate the product of the two charges. 2.2810 10 C (c) Solve for Q and Q using the two equations you got in part (a) and part (b). Hint: There are two possible solutions. Enter the answer with curly brackets as {Q1,Q} where Q is the smaller charge and Q2 is the larger charge. (c) {Q,Q} = X C
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a Using Coulombs Law F k Q Q r 02614 899 x 109 Q Q 28 02614 899 x 109 Q ...
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College Physics
Authors: OpenStax
2nd Edition
171147083X, 978-1711470832
