In the next sets, you are given the magnitude and one component. There is an ambiguity in determining the vector, because you can only determine the absolute value of the other component and not its sign; therefore, there are two possibilities. In these tables, you must enter the absolute value of the component and provide two angles for the vector, the first one assuming the other component is positive and the other assuming the component is negative. You must also provide two angles for the antiparallel vector in the same order. Set Set 5a 5b 6a 6b Ax ||Axl 37 -43 Ayl Ay 41 -30 Magnitude of A 80 85 Magnitude of A 68 52 Angle of A Angle of A (pos Ay) (neg Ay) O (pos Ay) o (neg Ay) O (pos Ax) (neg Ax) O (pos Ax) (neg Ax) O Angle of -A Angle of -A (pos Ay) (neg Ay) (pos Ay) O O (neg Ay) (pos Ax) (neg Ax) O (pos Ax) (neg Ax) O