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1) V Part A Two insulated wires perpendicular to each other in the same plane carry currents as shown in the figure (gure 1). Assume

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V Part A Two insulated wires perpendicular to each other in the same plane carry currents as shown in the figure (gure 1). Assume that I =10 A _ _ _ _ _ _ _ _ _ and d = 18 cm _ Find the magnitude of the net magnetic field these Wires produce at paints P and Q It the 10 A current Is to the right. Express your answers using two significant figures separated by a comma. .mC)? Riequest Answer V PaB Find the magnitude of the net magnetic field these wires produce at points P and Q it the 10 A current is to the left. Express your answers using two significant figures separated by a comma. .mC)? Figure 1 of1 Riequest Answer Provide Feedback 80 cm V Part A You want to produce a magnetic field of magnitude 5.50x10-4 T at a distance of 4.00x10-2 m from a long, straight wire. What current is required to produce this field? AEd ? I = 45 . 10 -7 A Submit Previous Answers Request Answer X Incorrect; Try Again; 3 attempts remaining V Part B With the current found in part A, how strong is the magnetic field 8.00 cm from the wire's center? B= 2.75 . 10e-4 T Submit Previous Answers Request Answer X Incorrect; Try Again; 5 attempts remainingPart A The 20.0 cm by 35.0 cm rectangular circuit shown in the figure ( Figure 1) is hinged along side ab. It carries a clockwise I = 5.35 A current and is located in a uniform 1.20 T magnetic field oriented Part B perpendicular to two of its sides, as shown. Calculate only the force that exert the torque mentioned in part A. AEd ? F = 1.2 N Submit Previous Answers Request Answer X Incorrect; Try Again; 5 attempts remaining Part C Figure Consider a wire of length L = 0.30 m that runs north-south on a horizontal surface. There is a current at I = 0.50 A flowing north in the wire. (The rest of the circuit, which actually delivers this current, is not shown.) The Earth's magnetic field at this location has a magnitude of 0.50 gauss (or, in SI units, 0.5 X 10'4 tesla) and points north and 38 degrees down from the horizontal, toward the ground. What is the size of the magnetic force on the wire due to the Earth's magnetic field? In considering the agreement of units, recall that 1 T : 1 N/(A . m).(EgLei) Express your answer in newtons to two significant figures. D View Available Hintts) X Incorrect: Try Again; 3 attempts remaining r Part B 'I The direction of the magnetic force is perpendicular to both the direction of the current flow and the direction of the magnetic field. Here is a "right-hand rule" to help you determine the direction of the magnetic force. (59%) 1. Straighten the fingers of your right hand and point them in the direction of the current. 2. Rotate your arm until you can bend your fingers to point in the direction of the magnetic field. 3. Your thumb now points in the direction of the magnetic force acting on the wire. N E D Part 0 ol > Part D Part A A rectangular 9.00 cm by 18.0 cm circuit carrying an 8.00 A current is oriented with its plane parallel to a uniform 0.770 T magnetic field (see the figure (Figure 1)). Find the magnitude of the magnetic force on each segment (ab, bc, etc.) of this circuit. Answer in the order indicated. Separate your answers with commas. AEd ? Fab, Foc, Fed, Fda = 0.55N,ON, - 0.55N,O N Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining Part B Part C Part D Figure 1 of 1 Part E 8.00 A Part F a Provide FeedbackV Part A An electron moves at 2.60x10 m/s through a region in which there is a magnetic field of unspecified direction and magnitude 7.00x10-2 T . What is the largest possible magnitude of the acceleration of the electron due to the magnetic field? ? a = 3.56e16 m/s2 Use the numeric value of e in your answer. No credit lost. Try again. Submit Previous Answers Request

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