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10. [0.5/1 Points] DETAILS PREVIOUS ANSWERS MY NOTES ASK Y The force F (in newtons) of a hydraulic cylinder in a press is proportional to

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10. [0.5/1 Points] DETAILS PREVIOUS ANSWERS MY NOTES ASK Y The force F (in newtons) of a hydraulic cylinder in a press is proportional to the square of sec(x), where x is the distance (in meters) that the cylinder is extended in its cycle. The domain of F is [0, n/3], and F(0) = 100. (a) Find F as a function of x. F(x) = 100 sec (x) (b) Find the average force exerted by the press over the interval [0, 7/3]. (Round your answer to one decimal place.) F = 250 X N

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