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10. (bonus 3 points, but not really hard). Given two sequences X and Y, both over the alphabet ABC.Z, we would like to generalize LCS
10. (bonus 3 points, but not really hard). Given two sequences X and Y, both over the alphabet ABC.Z, we would like to generalize LCS by allowing a character of X to be matched to multiple characters of Y, as long as the order between matched characters is not reversed. Figure 2 Lets call such a matching an order preserving matching. The goal is to maximize the number of paired edges. Suggest an O(|X|.|YD) time algorithm to compute the maximum matching. X = "ARAP NG X = "ARABANDO" IVAS Y = "A BRCFCOUR Y = "ABCFCOUR" Left: Maximum Order Preserving Matching. A single character of X could be matched to multiple characters of Y and vice versa. However, the corresponding segments could not cross each other. Right: This matching is not OP Matching, since some segments cross each other. Figure 2: Left: an example of the desired matching, where 5 pairs are matched. Right and an illegal match. 10. (bonus 3 points, but not really hard). Given two sequences X and Y, both over the alphabet ABC.Z, we would like to generalize LCS by allowing a character of X to be matched to multiple characters of Y, as long as the order between matched characters is not reversed. Figure 2 Lets call such a matching an order preserving matching. The goal is to maximize the number of paired edges. Suggest an O(|X|.|YD) time algorithm to compute the maximum matching. X = "ARAP NG X = "ARABANDO" IVAS Y = "A BRCFCOUR Y = "ABCFCOUR" Left: Maximum Order Preserving Matching. A single character of X could be matched to multiple characters of Y and vice versa. However, the corresponding segments could not cross each other. Right: This matching is not OP Matching, since some segments cross each other. Figure 2: Left: an example of the desired matching, where 5 pairs are matched. Right and an illegal match
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