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10 Consider the series k=1 14 20 10 Estimating the series using the partial sum of 20 terms, we see that Sn => 14 k=1
10 Consider the series k=1 14 20 10 Estimating the series using the partial sum of 20 terms, we see that Sn => 14 k=1 10 The remainder, Rn = /4 may be estimated using the Integral Test error estimate. k=21 Run Z and Rn
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