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10. (i) Find the equation of line perpendicular to line 3x-2y+5 =0 and passing through the point (1,3) (ii)Find equation of lines for which
10. (i) Find the equation of line perpendicular to line 3x-2y+5 =0 and passing through the point (1,3) (ii)Find equation of lines for which makes intercepts -3 and 2 on the x axis and y axis respectively.
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i To find the equation of a line perpendicular to the line 3x 2y 5 0 and passing through the point 13 we first need to determine the slope of the given line The line 3x 2y 5 0 can be rewritten in slopeintercept form as 2y 3x 5 y 32x 52 The slope of the given line is 32 Since the slope of a line perpendicular to a given line is the negative reciprocal of the slope of the given line the slope of the line perpendicular to 3x 2y 5 0 is 23 Using the pointslope form of the equation of a line we have y y mx x where x y 1 3 and m 23 Substitute the values into the equation and simplify y 3 23x 1 y 3 23x 23 y 23x 113 Therefore the equation of the line perpendicular to 3x 2y 5 0 and passing through the point 1 ...Get Instant Access to Expert-Tailored Solutions
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Step: 2
Step: 3
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