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10.1.2.x BW 100Mbps DLY 100 10.2.3.x BW 10Mbps DLY 1080 10.3.4.x BW 100Mbps DLY 100 10.4.5.x BW 100Mbps DLY 180 R1 R2 R3 R4 The

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10.1.2.x BW 100Mbps DLY 100 10.2.3.x BW 10Mbps DLY 1080 10.3.4.x BW 100Mbps DLY 100 10.4.5.x BW 100Mbps DLY 180 R1 R2 R3 R4 The following formula is used to calculate the composite metric for EIGRP. Which statement is correct? * Metric = 256 * ( 107 Total Delay + -) Min. Bandwidth 10 The Total delay is in ms Min Bandwidth is in kbps The reference bandwidth is 10^8 None of the above Use the Metric calculation for the 10.4.5.x network from the perspective of R4 to verify that the feasible distance FD is 28160 as shown in the below output: R4# show ip eigrp topology 10.4.5.0/24 IP-EIGRP (AS 99): Topology entry for 10.4.5.0/24 State is Passive, Query origin flag is 1, 1 Successor(s), FD is 28160 Composite metric is (28160/0), Route is Internal Vector metric: Minimum bandwidth is 100000 kbit Total delay is 100 microseconds Your answer Explain why the composite metric (feasible distance/reported distance) is (2816070) * Your answer Calculate the FD to the 10.4.5.x network from R3 through R4. Your answer * Find the missing values on the below R2 output: * R2# show ip eigrp topology 10.4.5.0/24 IP-EIGRP (AS 99): Topology entry for 10.4.5.0/24 A State is Passive, Query origin flag is 1, 1 Successor(s), FD is XXXXXX Routing Descriptor Blocks: 10.2.3.3 (FastEthernet0/0), from 10.2.3.3, Send flag is exe Composite metric is (XXXXXX/XXxxx), Route is Internal B 286720 30720 28160 268160 286720 32702 A B C C Based on your calculations, which 2 values will help R3 to determine whether R2 can be considered a Feasible successor for R3 to reach 10.4.5.x?* Your answer Consider that R1 is connected to the internet through GO/1, and connected to R2 through GO/O. Correct this EIGRP configuration. * Statements router ospf 1 ip route 0.0.0.0 G0/0 default-information originate ip hello-interval eigrp 10 10 Your

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