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Implement the three address code (2 marks) (11) Represent Directed Acyclic Graph of this three address code (1.5 marks) L10: S1=4* I S2 =

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Implement the three address code (2 marks) (11) Represent Directed Acyclic Graph of this three address code (1.5 marks) L10: S1=4* I S2 = addr (A) - 4 S3 = S2 [S1] S4 = 4* I S5 addr (B) 4 S6 S5 [S4] S7 = S3 * S6 S8 = Prod + S7 Prod = S8 S9 = I + 1 I = S9 If I

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