(11%) Problem 4: A uniform wooden meter stick has a mass of m = 699 g. A clamp can be attached to the measuring stick at any point P along the stick so that the stick can rotate freely about point P, which is at a distance d from the zero-end of the stick as shown P 8 9 10 11 12 13 14 15 16 17 18 Randomized Variables d ' m = 699 g Otheexpertta.com 17% Part (a) Calculate the moment of inertia in kgem of the meter stick if the pivot point P is at the 50-cm mark. La = 0.05800 Correct! 17% Part (b) Calculate the moment of inertia in kgem of the meter stick if the pivot point P is at the 0-cm mark d = 0 cm. Ib = 0.2330 Correct! 17% Part (c) Calculate the moment of inertia in kgem of the meter stick if the pivot point P is at the d = 25 cm mark. Ic = 0.10194 Ic = 0.1019 Correct! *17% Part (d) Calculate the moment of inertia in kg.m of the meter stick if the pivot point P is at the d = 81 cm mark. d = 0.51691 Grade Summary Deductions 0% Potential 100% sin() cos () tan() ST ( 7 8 9 HOME cotan() asin() acos() E 14 5 6 Submissions sinh() * 1 2 3 Attempts remaining: 997 atan() acotan() (0% per attempt) cosh() tanh() cotanh() +_ 0 END detailed view Degrees . Radians VO BACKSPA DEL CLEAR 0% N 0% Submit Hint Feedback I give up! Hints: 1 for a 0% deduction. Hints remaining: 0 Feedback: 0% deduction per feedback. -Apply the parallel-axis theorem, using the distance between the center of mass and the present pivot point. You found the moment of inertia with respect to an axis through the center of mass in part (a). 4 17% Part (e) Enter a general expression for the moment of inertia of a meter stick I. of mass m in kilograms pivoted about point P, at any distance d in meters from the zero-cm mark. 4 17% Part (f) The meter stick is now replaced with a uniform yard stick with the same mass of m = 699 g . Calculate the moment of inertia in kg.m of the yard stick if the pivot point P is 50 cm from the end of the yardstick