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(11%) Problem 5: A monatomic ideal gas initially fills a Vo = 0.35 m' container at Po = 65 kPa. The gas undergoes an isobaric

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(11%) Problem 5: A monatomic ideal gas initially fills a Vo = 0.35 m' container at Po = 65 kPa. The gas undergoes an isobaric expansion to V1 = 0.85 m'. Next it undergoes an isovolumetric cooling to its initial temperature To. Finally it undergoes an isothermal compression to its initial pressure and volume.$ 10% Part (c) Calculate the heat absorbed Oy, in kilojoules, during the isobaric expansion (first process). Grade Summary 21= 48.5071 Deductions Potential 100 sin() cos() tan() JI 7 HOME Submissions cotan() asin() acos() E TA A 5 6 Attempts remaining (0% per attempt) atan() acotan() sinh() 2 3 detailed view cosho tanh() cotanh() END 1 O Degrees O Radians VO BACKSPACE DEL CLEAR Submit Hint Feedback I give up! Hints: 2 for a 0% deduction. Hints remaining: 0 Feedback: 0% deduction per feedback. What is staying constant in this process? Make sure you use the appropriate molar specific heat equation. Use the Ideal Gas Law to write the temperature change in terms of the volume change. 10% Part (d) Write an expression for the change in internal energy, AU, during the isobaric expansion (first process). AU1 = 5/2 Po ( V1 - Vo ) - Po ( V1 - Vo ) Correct! A 10% Part (e) Calculate the work done by the gas, W2, in kilojoules, during the isovolumetric cooling (second process). A 10% Part (f) Calculate the heat absorbed O2, in kilojoules, during the isovolumetric cooling (second process). A 10% Part (g) Calculate the change in internal energy by the gas, AU2, in kilojoules, during the isovolumetric cooling (second process). 4 10% Part (h) Calculate the work done by the gas, W3, in kilojoules, during the isothermal compression (third process). A 10% Part (i) Calculate the change in internal energy, AU3, in kilojoules, during the isothermal compression (third process). 4 10% Part (j) Calculate the heat absorbed @3, in kilojoules, during the isothermal compressions (third process)

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