(11%) Problem 9: A baseball of mass m = 0.56 kg is spun vertically on a massless string of length L = 0.73 m. The string can only support a tension of max = 10.7 N before it will break. Randomized Variables m =0.56 kg L= 0.73 m Tmax = 10.7 N V 4 m X Otheexpertta.com *50% Part (a) What is the maximum possible speed of the ball at the top of the loop, in meters per second? Vt,max = 51 Grade Summary Deductions 0% Potential 100% sin() cos () tan() 7 8 9 HOME E TAAL 4 5 6 Submissions cotan() asin( acos() Attempts remaining: 995 atan() acotan() sinh() * 1 2 3 - (0% per attempt) cosh() tanh() cotanh() + 0 END detailed view o Degrees . Radians VO BACKSPA DEL CLEAR 0% 0% WN Submit Hint Feedback I give up! 0% Hints: 1 for a 0% deduction. Hints remaining: 0 Feedback: 1 for a 0% deduction -Start with a free body diagram, and then write down No meaningful feedback available for the current Newton's second law. At the top of the loop, gravity acts in submission. the same direction as tension. 4 50% Part (b) What is the maximum possible speed of the ball at the bottom of the loop, in meters per second