11. The back-side attack on 2-bromobutane by methoxide (CH3O) gives the product shown below. Which Fischer...

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11. The back-side attack on 2-bromobutane by methoxide (CH3O) gives the product shown below. Which Fischer projection represents 2-bromobutane used as the reactant in this reaction? Product Et = OCH3 Me H Et Br Me H- Br Br -H Me- H Br (b) Me (c) Et I (d) Et (a) Me- Et CH3-C=CH-CH2-C 12. The IUPAC name of COOC2H5 OH is : 13. (a) 4-ethoxycarbonylpent-3-enoic acid (b)4-ethanoyloxpent-3-enoic acid iksha (c) 3-ethoxycarbonylbut-2-enecarboxylic acid (d) 3-ethoxycarbonylpent-3-enoic acid The value of the spin only magnetic moment for one of the following configurations is 2.84 BM. The correct one is : (a) d (in strong field ligand) (b) d (in weak as well as strong field ligand) (c) d (in weak field ligand) (d) d* (in strong field ligand) 11. The back-side attack on 2-bromobutane by methoxide (CH3O) gives the product shown below. Which Fischer projection represents 2-bromobutane used as the reactant in this reaction? Product Et = OCH3 Me H Et Br Me H- Br Br -H Me- H Br (b) Me (c) Et I (d) Et (a) Me- Et CH3-C=CH-CH2-C 12. The IUPAC name of COOC2H5 OH is : 13. (a) 4-ethoxycarbonylpent-3-enoic acid (b)4-ethanoyloxpent-3-enoic acid iksha (c) 3-ethoxycarbonylbut-2-enecarboxylic acid (d) 3-ethoxycarbonylpent-3-enoic acid The value of the spin only magnetic moment for one of the following configurations is 2.84 BM. The correct one is : (a) d (in strong field ligand) (b) d (in weak as well as strong field ligand) (c) d (in weak field ligand) (d) d* (in strong field ligand)