12. An object is launched at 19.6 meters per second from a 58.8 meter tall platform. Theequation for the object's height s at time t seconds after launch is h(t) = -4.91² + 19.6t+58.8, where his in meters. When does the object strike the ground?a. t= -2 sec and t = 6b. t=0 secc. t = 2 secd. t = 6 sec