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1,2,3,4,5,6,7 Data Table I: Titration of HCl solution 1. Initial buret reading before titration (0.00mL) 2. Final buret reading after titration 0.00mL 3. Volume of

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Data Table I: Titration of HCl solution 1. Initial buret reading before titration (0.00mL) 2. Final buret reading after titration 0.00mL 3. Volume of NaOH used in the titration (2. minus 1.) 10.8mL 10.8mL 4. Volume of HCl sample titrated (put in flask) 10mk 5. Concentration of NaOH solution (read label on bottle) 0.0972M Data Table II: Titration of antacid Type/Brand of antacid used in Part II Mikk of Magnesia 1. Weight of empty flask 2. Weight of flask + antacid 3. Net weight of antacid (2. minus1.) 93.99q 1.01q195.00q 4. Volume of HCl added to antacid (put in flask) 50.00ma 5. Initial buret reading before titration (0.00mL) 0.00mL 6. Final buret reading after titration 41.70ML 7. Volume of NaOH used in titration (6. Minus 5.) 41.70mL 8. Concentration of NaOH solution (read label on bottle) 0.0972M 1. Calculate the concentration (in moles/liter) of the HCl solution titrated in Part I (equation \#1). The mathematical method of Dimensional Analysis (also called the Factor-Label Method) is used in equation #1 to calculate this HCl concentration. Check for all units to properly cancel. X volume in equation 1 is that calculated on table I, line 3. 2. Calculate the total number of moles contained in the 50mL of excess HCl added. (equation #2 ). 3. Calculate the moles of excess un-reacted HCl neutralized by NaOH in Part II (use equation \#3). This calculated amount is how much HCl was left un-reacted after the antacid initially neutralized a portion of the total HCl solution. Check for all units to properly cancel. Use volume calculated on table II line 7. 4. Calculate the number of moles of HCl neutralized by antacid, Subtract the total number of moles of HCl added (in question 2 above) minus the number of molacid, Subtract the total number of moles of above) (use equation H4 ). 5. To convert moles HCl neutralized by antacid to volume of HCl. multiply by the reciprocal of molarity of HCl. ( equation \#5). Use the HCl concentration calculated in question 1 as one conversion factor and convert to mL. 6. Using your answer from question 5 , and assuming that a dilute solution of HCl has a density of approximately 1.00g/mL, calculate the weight in grams of HCl solution initially neutralized by the antacid (use equation \#6). Check for all units to properly cancel. 7. Based on your answer to question 6 above, and the net weight of antacid from Data Table II, this antacid consumes how many times its own weight in stomach acid (dilute HCl )

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