125 lb (0, 0) } 2 (10, 15) C 25 lb (a) Design 1 (30, 15) 4 (20, 0) (a) Design l Case I E = 30 x 10 psi Case 2 E = 10 10 psi * R5 (32, 11.25) (38, 0) 115 | 2 wwwwwww 25 lb (b) Design 2 .6 2 (10, 15) (30, 15) 5 A, = (0I in2 42 = A = A = 1, = 0.15 in.2 4 = A, = 4, 0.3 in 1, = ()01 iI1.* (20, 0) (b) Design 2 Problems 26 (32, 11.25) 2 - }}= 1 = 1 = 0,02 in.+ I = 1, - 1 = 0.1 in.+ Figure P5-25 Two bicycle frame models (coordinates shown in inches) (38, 0)