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13 10.00 ml of acetic acid was titrated with 35.00 ml of 0.10 M NaOH solution, according to the following equation: CH3COOH + NaOH CH3COONa
13 10.00 ml of acetic acid was titrated with 35.00 ml of 0.10 M NaOH solution, according to the following equation: CH3COOH + NaOH CH3COONa + H20 (M.W of Acetic acid = 60 g*mol, Density of Vinegar = 1.05 g/ml) Calculate Mass % of acetic acid. (2 Points) 1% 2% 3% 4%
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