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13) [T/ F , 1 /4 7 The angular and linear accelerations of and a are related as a = Ra 14 ) ['s ]

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13) [T/ F , 1 /4 7 The angular and linear accelerations of and a are related as a = Ra 14 ) ['s ] Use your answers to problems 10 and 1 to solve for the acceleration a in terms of F and m. The result is a) a = Ftig b ) a = F-my M - m m+ Wa ca= F+ mg d ) a = F-mg Mti m + M 2) a= _ F - mg M / 2 - m (Hint : using the correct expression for d in terms , a one sbrains two egs for the two unknowns Tand a ) 15) [TIF, 1/4 ] Taking into account the numerical values o M, M , F , R , the angular acceleration is f = 10.2 rad / 29 ) [ '/ 2 ] which of the following force diagrams correctly depicts the forces acting on the pulley and on the bloke ? a ) b ) T ( ) L F 9 FAT 10 ) [ 2 1 How do T and f compare ? a ) T > F b J F > T c ) F = T 1 12 5 12 I which of the following is Nanton's and law applied to the block : a ) T - mg = ma b ) F - mg = a ( ) mg- T = ma d ) ma - F = a 12 ) [ 1 /2 J which of the following is NewBB's and law of rotation for the pulley, where of is the pulley's angular acceleration , and I is the forque on the pullen ? (recall I= ' iMR 2 ) a T = FR - Id bj T = ( F- T ) Q = Id c ) 1 : TR = Id d ) N = ( T - FJ R = 12In Fig 1 a string passes over a pulley . A Brae F pulls on one end of the string , and a block of mass in is attached to the other end of the string. The block is Initially at rest and accelerates upwards after F is applied , with a constant acceleration a . The pulley rotates w/ out experiencing any friction, and the string does not slip or stretch and can be taken to be massless. I=L MR2 R Fig. 2 FV m . The pulley has moment of inertin I=IMR?. The mass of the block s m = = kg, R= 1 m, M=1kg and -= ION. . Let I be the tension in the string

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