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14. Given the thermochemical equations X2 + 3 Y2 2XYZ AH = -390 kJ X, +2Z2 = 2 XZ AH2 = -170 kJ 2 Y2

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Given the thermochemical equations X2 + 3 Y2 2XYZ AH = -390 kJ X, +2Z2 = 2 XZ AH2 = -170 kJ 2 Y2 +Z_ 2Y,Z AH3 = -250 kJ Calculate the change in enthalpy for the reaction. 4XYZ + 722 > 6Y,Z+4XZ AH= KJ

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