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15. Consider the following program max min.c 1 #include 3 void nax_min(int a, int n, int max, int min) 5 int main(void) 6 ( int

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15. Consider the following program max min.c 1 #include 3 void nax_min(int a, int n, int max, int min) 5 int main(void) 6 ( int at]-i6, 8, 14, 5, 9, 23, 45, 651 int max a, min a: 10 max min(a, 8, smax a, min a): printf("max is ed and nin is %din", nax-a, mina); return 0 12 13 14 15 16 vold max_min(int a, int n, int nax, int min) 17 E 18 int p 19 "max "min-a 20 for Gp

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