15c. Set up a 95% CI for the sample mean, using your values of M, s, and N (N = 130 in this data set). For both: use z = -1.96 and z = + 1.96 to correspond to middle 95% of the area of the sampling distribution. Answer for Fahrenheit scale scores: Limits of 95% CI: M 1.96 * SEM = 98.243 1.96 * .0627 98.243 .1229 = 98.12 to 98.37 Answer for Centigrade scale scores: Limits of 95% CI: M 1.96 * SEM = 36.80 1.96 * .0348 36.80 .0682 = 36.73 to 36.87

QUESTION

What can you conclude from these computations and analysis.?