19 / 28 / 2021 (part1 Integrate COSX ex ex 16 sin x + 25 (x-2) V X2-4x-5 3x dx (/24+203X 06x party Integrate , use partial fractions 3 x 1 5X 4 + 6 8 (6* 2 + 17X -5 dx * 2 ( x + 5 ) 4 Inx ex X VIn 2x - 1 6 -x+3x2+ 2x - 9 ex ( x 2- 2 ) (x2- 3 ) 5) 1 - 8X 2 lux dx X VInyx + 8 2 x + 11 SHOW ALL WORK to receive credit. In part 1, use only one u-substitution and identify that formula from the given integral table to obtain final answers. Or send pictures to my cell phone - I '/ du = In |u|+ c Su" du = 0+1 -+ c , n#-1 n+1 du 16. du Jaz - uz 5 = arcsin ~ + C 17. a2 + u2 - - arctan " + c 18. du u Juz - a2 = = arcsec ec lul' + c : a du = In( u+ u + a? ) + . C 9 . Just a 1. .. 20 . du a2 - 412 - 2 1 a tu +c 2a la - u 12 - az du = - Inju -a + c 2a 21. du 1 at a tu lul. + .C