19 [8] A heated material left to cool wi|| radiate heat as well as heat the immediate I surrounding air. The tabulated data was collected from a saucepan with water on a kitchen stove. nm- The hotter the saucepan, the quicker the temperature will drop as time passes. Isaac Newton observed the behaviour and derived his law of cooling for) = Tm + {T(t = n) _ 1191\T(t) material (water) temperature at time t Tenv the environment temperature (kitchen or room temperature) Dec 2020 .... real data provided. Tenv = 28 C T(t=0) 89 C measured, at start of cooling time t= 0 T time constant for the system in review (pronounced tuff)a/ [2] Transpose, making t (pronounced tuff) the subject ? b/ [2] For all the tabulated time - temperature values, determine the associated I values. Then calculate the mean time constant value 7 Answer: 7 = 1,208 sc/ [2] Graph the measured temperature AND t against time ie T and t verses t (sec) d/ [2] Using the original expression updated with mean time constant - 7 determine the temperature at times i/ 834 seconds ii/ 16.5 minutes