19. If logg5 = x and log276 = y, find an expression in terms of x and y for log3 1.2 log5 / log 9 = X log6 / log 27 = y log 5 / log3^2 = X log 6 / log3 3 = y log 5 / 2 log 3 = x log 5 / 3 log 3 = y (1/2) (log 5 / log 3) = x (1/3) (log 6 / log 3) = y (1/2) 1093 5 = X (1/2) 1093 6 = y 1093 5 = 2x log3 6 = 3y log3 6 - log3 5 = 3y - 2x log3 (6/5) = 3y - 2x log3 (1.2) = 3y - 2x