1.A Chi square test has been conducted to assess the relationship between marital status and church attendance. The obtained Chi square is 23.45 and the critical Chi square is 9.488. What may be concluded?

A.Reject the null hypothesis, Church attendance and marital status are dependent

B.Reject the null hypothesis, church attendance and marital status are independent

C.Fail to reject the null hypothesis, church attendance and marital status are dependent

D.Fail to reject the null hypothesis, church attendance and marital status are independent

2.In a research study conducted to determine if arrests were related to the socioeconomic class of the offender, the chi square critical score was 9.488 and the chi square test statistic was 12.2. We conclude that:

A.the variables are independent

B.Being in a certain socioeconomic class triggers arrest

C.the variables are dependent

D.the probability of getting these results by random chance alone is 0.5

3.How many degrees of freedom does a 3 x 3 bivariate table have?

A.8

B. 6

C. 4

D.3

4. In the Chi square test for independence, the null hypothesis and the research hypothesis

a. always contradict each other

b. always agree with each other

c. are never actually stated

d. are usually both rejected

5. a researcher reports that her obtained chi square of -17.56 is significant because it exceeds the critical chi square of -3.841 for an alpha of .05 with 2 degrees of freedom. What mistake has been made?

a. neither critical nor obtained chi square can have negative values

b. it is impossible to have only 2 degrees of freedom

c. it is impossible for obtained Chi square to exceed 10

d. One- tailed test should have been used

6. In the Chi square test, expected frequencies are computed by

A. adding the observed frequency to N and subtracting the number of cells

b. adding the observed frequency to N and subtracting the number of cells

c. Multiplying the observed frequencies by the row marginals and dividing by degrees of freedom

d. adding the proper row and column marginals together and dividing by N

7. When the null hypothesis in the Chi square test for independence is true, there should be:

A.Large difference between the observed frequencies and the expected frequencies

B.Little difference between the observed frequencies and the expected frequencies

C.No difference between the observed frequencies and the marginal

D.No difference between the row and the column marginal

8. In the chi square test of hypothesis, the null hypothesis states that the variables are

a. Dependent

b. independent

c. causally related

d. non-random