1.An open channel is V-shaped, each side being inclined at 45 to the vertical.If the rate of flow is 0.0425 m³/s when the depth of water at the centre is 0.225 m, calculate the slope of the channel using Chezy's formula assuming that C = 49 in SI units.

2.Assuming that the frictional resistance to flow in an open channel is proportional to the square of the mean velocity, derive the Chezy formula.What is the dimension of C?

3.A channel has vertical walls 1.2 m apart and a semicircular invert.If the centre-line depth is 0.9 m and the bed slope is 1:2500, what is the value of C in the Chezy formula if the discharge is 0.55 m³/s?

4.Show that for a circular culvert of diameter D, the velocity of flow will be a maximum when the depth of flow h at the centre is 0.81D.Use Chezy formula.

A sewer, diameter D = 0.6 m, has a slope of 1 in 200.What will be the maximum velocity of flow that can occur, and what is the discharge at this velocity?Assume C = 55 in SI units.

5.A 0.9 m diameter pipe is to have a maximum discharge Q of 0.7 m³/s, and it is found that the mean velocity is given by V= 67R^2/3S^1/2.Calculate the required value of the gradient.

6.The Kutter's and Bazin's formulae for the Chezy coefficient are given as follows:

Kutters's formula: