1.Use the crossing graphs method to solve the given equation.

x2+3x12=x+3

a)x=15andx=1

b)x=5andx=3

c)x=15andx=1

d)x=5andx=3

e)x=5andx=3

2.Use the single graph method to solve the given equation.

681+2xx=0

a)x=3

b)x=7

c)x=4

d)x=5

e)x=1

3.Use the crossing graphs method to solve the following, where represents revenue, and represents cost.

R(x)=44+7xx2C(x)=7x77

Note that a negative answer is extraneous and can be discarded. Report only the positive answer.

a)x=11

b)x=121

c)x=33

d)x=1212

e)x=33

4.Solve for x:

60011+17x=2

a)x=3

b)x=4

c)x=2

d)x=4913

e)x=17

5.Solve for x:

x216=12

a)x=2orx=0

b)x=1orx=4

c)x=16

d)x=2orx=2

e)x=2orx=0

6. Find the place or places where the graph crosses the x-axis.

f(x)=10ex(x7)

a)x=10

b)x=7

c)x=0,x=7

d)x=0,x=10,x=7

e)x=e,x=7

7.

Given the following function, find the point where the maximum occurs.Round coordinates to the nearest hundredth.

f(x)=5x2+21x19

a)(0.12, 16.57)

b)(0.00, 19.00)

c)(2.10, 3.05)

d)(4.20, 19.00)

e)(1.90, 76.95)

8. Given the following function, find the point where the minimum occurs.

f(x)=x212x5

a)(12,5)

b)(6,41)

c)(6,39)

d)(12,5)

e)(0,5)

9. Find the maximum value of the following function on the interval[2,1]. Round to the nearest hundredth if necessary.

f(x)=(x3)(x+1)(x2)

a)10

b)2.87

c)4

d)20

e)6.06

10. Find the minimum value of the following function on the interval[1,4]. Round to the nearest hundredth if necessary.

f(x)=(x3)(x+1)(x2)

a)10

b)0

c)2.83

d)0.88

e)4