1)What is the subnet mask for the initial network 172.16.128.0 /21?

255.255.248.0

255.255.240.0

255.255.252.0

255.255.247.0

2)What is the Network IP for each of the 4 LANs?

172.16.129.192

172.16.129.0

172.16.129.128

172.16.128.0

LAN-A

LAN-B

LAN-C

LAN-D

LAN-A

LAN-B

LAN-C

LAN-D

3)Determine the ip address of each router interface IP as follows: *

172.16.128.2

172.16.129.202

172.16.129.129

172.16.129.126

R1 (G0/1 1st host)

R1 (G0/2 10th host)

R2 (G0/1 2nd host)

R2 (G0/2 last host)

R1 (G0/1 1st host)

R1 (G0/2 10th host)

R2 (G0/1 2nd host)

R2 (G0/2 last host) 4)

Determine the subnet mask for each network. *

255.255.255.192

255.255.255.128

255.255.255.0

255.255.255.224

LAN-A

LAN-B

LAN-C

LAN-D

LAN-A

LAN-B

LAN-C

LAN-D 5)Determine the Default-gateway IP address for each PC device. *

172.16.128.2

172.16.129.129

172.16.129.202

172.16.129.126

172.16.128.3

PC-A

PC-B

PC-C

PC-D

PC-A

PC-B

PC-C

PC-D 6)Determine the PCs IP addresses as follows *

172.16.128.10

172.16.129.190

172.16.129.1

172.16.129.193

172.16.1.1

172.16.129.191

PC-A (last valid ip)

PC-B (2nd valid ip)

PC-C (10th valid ip)

PC-D (1st valid ip)

PC-A (last valid ip)

PC-B (2nd valid ip)

PC-C (10th valid ip)

PC-D (1st valid ip)

Consider the below topology with LANs A,B,C and D and answer the following questions. LAN-C 250 users LAN-A: 60 users PCA SWA SW-C PCC G0/1 G0/1 G0/2 R1 RC G012 PCB SW-B SW-D PCD LAN-D. 120 users LAN-B: 24 users VLSM for the initial network 172.16.128.0 121