$(20$ points$)$ Consider the following fragments of unrelated E$15$ assembly language programs $($ a and $b)$ and $E15$

machine language code $(c)$ :

$($a$)$

$8421$

$lg3=13$

$l{g}^2=8$ teroflag $1$

$[8]=\{movi,Rxx,Rg3,4^{\text{'}}b1101\}$;

mevi, $Rxx,Rg3,4^{\text{'}}b1000$

What is the address of the instruction that will be executed immediately after the instruction at address

$11?$ Give your answer in decimal. If the address of the next instruction cannot be determined from the

information given, explain why.

zere flag is $84$ to $1.$ Hence jump $($jz$)$ happens by

$pc+$ imm $=11+15.$

It will overflow and go to Rom $[0].$ Answer:$0.$

$($b$)$

myRom $[8]=\{$ movi, $RXX,Rg0,4\text{'}b0100\}$; Rgo$=4$

myRo$[9]=\{\begin{array}{c}cmp\\ Rg0\\ Rg2\\ 4^{\text{'}}\end{array}b0000$

What is the address of the instruction that will be executed immediately after the instruction at address

$10?$ Give your answer in decimal. If the address of the next instruction cannot be determined from the